Tolong Bantu kak untuk menjawab latihan ini
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Jawaban:
2.155
Penjelasan:
pH = - log [H]
[H] = akar Ka x M
Molaritas = 0,001 M = 10^-3
[H] = akar 49 x 10^-3 x 10^-3
[H] = 7 x 10^-3
pH = - log (7 x 10^-3)
pH = 3 - log 7
pH = 2.155
Jawaban:
2.155
Penjelasan:
pH = - log [H]
[H] = akar Ka x M
Molaritas = 0,001 M = 10^-3
[H] = akar 49 x 10^-3 x 10^-3
[H] = 7 x 10^-3
pH = - log (7 x 10^-3)
pH = 3 - log 7
pH = 2.155